Families that Remain $k$-Sperner Even After Omitting an Element of their Ground Set
Abstract
For pairs of integers $l<k$, if in a family $\mathcal{G}$ every pair of sets satisfies $||G_1|-|G_2||<k-l$, then $\mathcal{G}$ possesses the $(n-l)$-trace $k$-Sperner property. Among such families, the largest one is $\mathcal{F}_0=\{F\in 2^{[n]}: \lfloor \frac{n-(k-l)}{2}\rfloor+1 \le |F| \le \lfloor \frac{n-(k-l)}{2}\rfloor +k-l\}$ and also $\mathcal{F}'_0=\{F\in 2^{[n]}: \lfloor \frac{n-(k-l)}{2}\rfloor \le |F| \le \lfloor \frac{n-(k-l)}{2}\rfloor +k-l-1\}$ if $n-(k-l)$ is even.
In an earlier paper, we proved that this is asymptotically optimal for all pair of integers $l<k$, i.e. $f(n,k,n-l)=(1+o(1))|\mathcal{F}_0|$. In this paper we consider the case when $l=1$, $k\ge 2$, and prove that $f(n,k,n-1)=|\mathcal{F}_0|$ provided $n$ is large enough. We also prove that the unique $(n-1)$-trace $k$-Sperner family with size $f(n,k,n-1)$ is $\mathcal{F}_0$ and also $\mathcal{F}'_0$ when $n+k$ is odd.