The Electronic Journal of Combinatorics

v3i2r18 — Comment by Marc van Leeuwen (CWI, Amsterdam), Dec 11, 1996.

  • at the end of section 3 (page 10) it is claimed that all maximal parabolic subgroups are isomorphic, and even conjugate. The first is true, the second is not (despite the fact that for $n\gt 2$ all $n$ generators $s_i$ are individually conjugate).
  • In equation (10), the variable $i$ should run over all integers, rather than the positive ones, in order to get obtain right value for negative $j$ (in particular to ensure that $\mathrm{Inv}_j(\sigma)=\mathrm{Inv}_{j+n}(\sigma)$ as claimed shortly after the equation).